Question

given that g(×)=ac{x - 3}{x + 4} " alt=" \frac{x - 3}{x + 4} " align="absmiddle" class="latex-formula">find each of following.a) g(6)b) g(3)c) g(-4)d) g(-15.75)e) g(x+h)

Answer 1

ANSWER:

$\begin{gathered} a)\text{ 6} \\ b)\text{ 0} \\ c)\text{ inderminate} \\ d)\text{ 1.6} \\ e)\text{ }\frac{x+h-3}{x+h+4} \end{gathered}$

STEP-BY-STEP EXPLANATION:

We have the following function

$g(x)=\frac{x-3}{x+4}$

Now, we calculate for each case the result of the function.

a) g(6)

$g(6)=\frac{6-3}{6+4}=\frac{3}{10}$

b) g(3)

$g(3)=\frac{3-3}{3+4}=\frac{0}{7}=0$

c) g(-4)

$g(-4)=\frac{-4-3}{-4+4}=-\frac{7}{0}=\text{ inderminate}$

d) g(-15.75)

$g(-15.75)=\frac{-15.75-3}{-15.75+4}=\frac{-18.78}{-11.75}=1.59\cong1.6$

e) g(x+h)

$g(x+h)=\frac{x+h-3}{x+h+4}$