Find the least number which must be added to 6203 to obtain a perfect square.

Mathematics

1 answer:

cluponka [151]4 years ago

6 0

Answer:

78.7591264553

Step-by-step explanation:

search google

copy answer sorry that is all I got

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$\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}$

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

$\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}$

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Step-by-step explanation:

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