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3 years ago

Is 9/15 irrational??

Mathematics

2 answers:

Mariana [72]3 years ago

4 0

No because irrational cant be a simple fraction and 9/15

is 0.6

so... it is not irrational

ch4aika [34]3 years ago

3 0

Hi Madison!

A rational number is a number that cannot be expressed as a ration between two integers.

So Irrational number are like 3.14.

I searched a chart of numbers and it looks like that fraction will actually be considered an rational number, not irrational.

Hope this helps!

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Grocery store sella kiwis for $4.25 a pound and Asian pears for $2.25 a pound. Write an equation in standard form using integers

bogdanovich [222]

The pears could equal exactly $18

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3 years ago

Y = 3x + 5, x = -4 / So, what would the y in the equation equal to ?

3241004551 [841]

Answer:

Step-by-step explanation:

y= 3 (-4)+5

y= - 12+5

y= -7

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3 years ago

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The two objects are the same height, and the cylinder is just wide enough for the the box to fit inside with all 4 vertical edge

OLEGan [10]

Answer:

The answer is below

Step-by-step explanation:

The volume of a box with a length of l, width of w and a height of h is given by the formula:

volume of the box = length * width * height = lwh

The volume of a cylinder with a height of h, and radius r is given by the formula:

volume of the cylinder = π * radius² * height = πr²h

Since the box and the cylinder have the same height and the cylinder is wide enough for the box to be placed inside, this means that the box has a volume greater than that of the cylinder. Hence:

If the box can take 8 cups, the cylinder would be able to take 10 cups.

7 0

2 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

6 0

3 years ago

Express 160 as product of their prime factor

MariettaO [177]

Answer: 5x2^5

Step-by-step explanation: Divide 160 by 2 as many times as you can to get 80x2, 40x2x2, 20x2x2x2, 10x2x2x2x2, 5x2x2x2x2x2. Then re-write your answer so that it is 5x2^5.

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2 years ago