By normal curve symmetry
<span>from normal table </span>
<span>we have z = 1.15 , z = -1.15 </span>
<span>z = (x - mean) / sigma </span>
<span>1.15 = (x - 150) / 25 </span>
<span>x = 178.75 </span>
<span>z = (x - mean) / sigma </span>
<span>-1.15 = (x - 150) / 25 </span>
<span>x = 121.25 </span>
<span>interval is (121.25 , 178.75) </span>
<span>Pr((121.25-150)/25 < x < (178.75-150)/25) </span>
<span>is about 75%</span>
Coordinates are written in the form (x,y), x being a certain length along the horizontal x axis and y being a certain height along the vertical y axis. Positive y numbers are in the top half of the plane and negative y numbers are on the bottom. Positive x numbers are on the right side of the plane and negative x numbers are on the left. Therefore, (3,-7) would be 3 across to the right from the origin (where the x and y axes intersect) at (3,0) and 7 downwards from that point to (3,-7).
Answer:
800m
Step-by-step explanation:
this would be solved using Pythagoras theorem
we are to find the base
The Pythagoras theorem : a² + b² = c²
where a = length
b = base
c = hypotenuse
600² + b² = 100²
b² = 10000 - 3600
b² = 6400
take the square root of both sides
b = 800m
Answer:
2h 1' 1"
Step-by-step explanation:
1h = 1 hora
1' = 1 minute
1" = 1 secind
The sum of the three days is:
58' 45"
+ 40' 40"
20' 36"
= 118' 121"
118' 121" = 118' + 121"
1' = 60"
121" = 120" + 1" = (120/60) + 1 = 2' + 1"
Then:
118' + 121" = 118' + 2' ´+ 1" = 120' + 1"
1 h = 60'
(120/60) + 1 = 2h + 1'
then:
118' + 121" = 2h + 1' + 1"
= 2h 1' 1"
There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
' in a right triangle, '
' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:
Now, we solve for x:
So, answer is 3.4
