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kirill115 [55]
2 years ago
11

I'm trying to figure this out, but I can't get it

Mathematics
2 answers:
oksano4ka [1.4K]2 years ago
8 0

\\ \sf\longmapsto \sqrt{16r^6}

\\ \sf\longmapsto \sqrt{16}\sqrt{r^6}

\\ \sf\longmapsto 4r^{6\times \dfrac{1}{2}}

\\ \sf\longmapsto 4r^3

Option B is correct

Katen [24]2 years ago
5 0

Answer:

\sqrt{16 {r}^{6} } \\ ( \sqrt{16 {r}^{6} } )^{2} \\ (4 {r}^{3} )

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Your answer should be a polynomial in standard form (9+q)(8-q)
xxMikexx [17]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
1.
Nana76 [90]

Answer:

12 feet

Step-by-step explanation:

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Hope this helps.

8 0
4 years ago
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Step-by-step explanation:

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5 0
3 years ago
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Elodia [21]
The answer to this question is 22
8 0
3 years ago
Read 2 more answers
If a line of one billion people stretched 327,495 miles long, the average shoulder width of the people in the line is A feet. Ro
Ganezh [65]

Answer:

  1.7 ft

Step-by-step explanation:

We presume you want to find A. And we presume the people are standing shoulder-to-shoulder.

  (327,495 mi)/(10^9 persons) = (3.27495×10^5 mi)/(10^9 persons) × (5280 ft/mi)

  = 1.7291736×10^9 ft/(10^9 persons)

  = 1.7292736 ft/person

  ≈ 1.7 ft/person

3 0
3 years ago
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