Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
maybe
Step-by-step explanation:
Dora is apparently assuming the dimensions are integers. In that case she is correct.
If the dimensions are unconstrained, the perimeter will be largest when a pair of opposite sides will be the smallest measure allowed.
For some perimeter P and side length x, the area is ...
A = x(P/2 -x)
Conversely, the perimeter for a given area is ...
P = 2(A/x +x)
This gets very large when x gets very small, so Dora is correct in saying that the side lengths that are as small as they can be will result in the largest perimeter. We have no way of telling if her assumption of integer side lengths is appropriate. If it is not, her statement makes no sense.
Answer:
a=72 and b=36
Step-by-step explanation:
A=2B
A-10-13=B+13
Answer:
The numbers are 21 and 33
Step-by-step explanation:
54/2=27
27-6=21
27+6=33