Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
You didnt include the (presumably) multiple choice answers. My guess is that the answer would be along the lines of: 20 - (P times .40)
2/9(x)9/4 =18/36
1/2
2/9(x)-9
-18/9
-2
Answer:: y=1/2x-2
1 dry quart=1.10
1.10 x 4= 4.4
Final answer: B.
The answer choice is B I just took