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34kurt
1 year ago
11

Complete the table for each function. Then answer the questions that follow.X Y=4x Y=4x^2 Y=4^x0 0 0 11 4 a b2 c 16 d3 e f ga=?

b=?c=?d=?e=?f=?g=?

Mathematics
1 answer:
GenaCL600 [577]1 year ago
7 0

Let's evaluate each function for the integers from 0 to 3:

undefined

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Answer:

The equation that would be used for the zero product property on will be (x-5)(x-10)=0

Option B is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{(x-4)}+1=\frac{14}{x+2}

Solving the equation:

\frac{1}{(x-4)}+1=\frac{14}{x+2}\\\frac{1+(x-4)}{x-4}= \frac{14}{x+2}\\\frac{1+x-4}{x-4}= \frac{14}{x+2}\\\frac{x-3}{x-4}= \frac{14}{x+2}\\Cross\: Multiply\\(x-3)(x+2)=14(x-4)\\x(x+2)-3(x+2)=14x-56\\x^2+2x-3x-6=14x-56\\x^2-x-6-14x+56=0\\x^2-x-14x-6+50=0\\x^2-15x+50=0

Now, we would factorise to find value of x

x^2-15x+50=0\\x^2-5x-10x+50=0\\x(x-5)-10(x-5)=0\\(x-5)(x-10)=0

So, the equation that would be used for the zero product property on will be (x-5)(x-10)=0

Option B is correct.

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3 years ago
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