I would say it is B!... there are dense, positive charged mass in the center of the atom
1) variation in traits.
population of beetles: equal brown and green numbers in population.
2) differential reproduction.
Natural habitat is in trees. Green leaves hide green beetles.
The brown beetles are noticed by birds in the area.
Birds eat brown beetles.
More green beetles survive than brown beetles
3) heredity
Green beetles reproduce in greater numbers than brown beetles
4) end result
Beetle population changes from brown and green to mostly green beetles.
Lets calculate the parameters of the problem. Suppose that the width is x feet. THen, the length is x+30 feet. The area of this parallelogram is given by the product of length and width, hence x(x+30). This has to be equal to 600.
Hence, x is the solution to the equation x(x+30)=600.
x*x+30x=600 hence x*x+30x-600=0. This is a second degree equation and we can calculate Δ=b*b-4ac=3300. The general solution is given by:

.
Substituting, we get that x=-30/4+

or x=-7.5+25*

. This is the width; the length is given by x+30.