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ollegr [7]
10 months ago
9

24 people divided among three elevators how many people are in each elevator

Mathematics
2 answers:
emmasim [6.3K]10 months ago
7 0

Answer:

24 divided by 3 is 8 so use long division

RSB [31]10 months ago
4 0

Answer:

Step-by-step explanation:

24/3 = 8

8 people in each elevator

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Which of the following trigonometric ratios are correct?
notka56 [123]

9514 1404 393

Answer:

  D, F

Step-by-step explanation:

The mnemonic SOH CAH TOA can help you with this. It reminds you ...

  Sin = Opposite/Hypotenus

  sin(40°) = x/b . . . . matches D

  Cos = Adjacent/Hypotenuse

<em>   cos(40°) = a/b . . . . no match</em>

  Tan = Opposite/Adjacent

  tan(40°) = x/a . . . . matches F

8 0
2 years ago
PLEASE ANSWER ASAP!!!!
Arlecino [84]

We'll use the notation \textrm{Arcsin } x for the principal value and \arcsin x for all the values:


\arcsin x = \textrm{Arcsin } x + 2\pi k \textrm{ or } (\pi - \textrm{Arcsin }x) + 2\pi k \quad \textrm{ integer } k


Part I


\sin(\theta/2) = \frac 1 2


\theta/2 = \arcsin \frac 1 2


Part II. In our range we can write


\sin(\theta/2) = \sin(\frac \pi 6)


\theta/2 = \frac \pi 6 \textrm{   or   } \theta /2 = \pi - \frac \pi 6 = \frac{5\pi}{6}


Part III.


\theta = \frac \pi 3 \textrm{   or   } \theta = \frac{5\pi}{3}


Part IV.


\theta/2 = \frac \pi 6 + 2\pi k \textrm{ or } \theta = \frac{5 \pi}{6} + 2\pi k \quad \textrm{integer } k

\theta = \frac \pi 3 + 4 \pi k \textrm{   or   } \theta = \frac{5 \pi}{3} + 4\pi k  \quad \textrm{integer } k



5 0
2 years ago
59:46
grin007 [14]

Answer:

The answer is 11.2 cm

Step-by-step explanation:

4 0
3 years ago
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Ricardo S. gave 158 baseball cards to Ayden and 45 cards to Conner. He had 42 cards left. how many baseball cards did Ricardo S.
Inessa05 [86]

Answer:

203 ;  245

Step-by-step explanation:

158 + 45= 203

question 2

203+42= 245

3 0
3 years ago
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100 POINTS!!!!
weeeeeb [17]

Answer:

O is the center of the circle with radius IE(=ID=EF)

Step-by-step explanation:

Join all 3 points D, E, F, forming the triangle DEF.

Let the midpoint of EF be M and the midpoint of ED be N. (first picture)

Join point I to E, D and F.

Since IN is both an altitude and median to triangle EID, then triangle EID is an isosceles triangle, and IE=ID

similarly, we see that IE=IF.

conclusion: IE=ID=EF.

5 0
2 years ago
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