Answer:
Part 1) The domain of the quadratic function is the interval (-∞,∞)
Part 2) The range is the interval (-∞,1]
Step-by-step explanation:
we have

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)
step 1
Find the domain
The domain of a function is the set of all possible values of x
The domain of the quadratic function is the interval
(-∞,∞)
All real numbers
step 2
Find the range
The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.
we have a vertical parabola open downward
The vertex is a maximum
Let
(h,k) the vertex of the parabola
so
The range is the interval
(-∞,k]
Find the vertex

Factor -1 the leading coefficient

Complete the square


Rewrite as perfect squares

The vertex is the point (7,1)
therefore
The range is the interval
(-∞,1]
It’s already in ascending order.
3/5= .6
5/8= .625
5/6= .833
7/4= 1.75
a= 16x+16
b= 40x + 15
Step-by-step explanation:
We know that perimeter of a rectangle is

So therefore



Answer= A) that is perimeter is 16x+16
We know that area of a rectangle is l×b
So therefore


Answer = b) that is area is 40x + 15
<em>(2a - 3x - 3y)(2a + 3x + 3y)</em>
- Step-by-step explanation:
<em>Hi there !</em>
use formula
<em>a</em><em>² - </em><em>b</em><em>² = (a - b)(a + b)</em>
<em>a</em><em> = 2a</em>
<em>b</em><em> = 3(x + y)</em>
<em />
<em>4a² - 9(x+y)² =</em>
<em>= [2a - 3(x + y)][2a + 3(x + y)]</em>
<em>= (2a - 3x - 3y)(2a + 3x + 3y)</em>
<em />
<em>Good luck !</em>