Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
Answer:
49
Step-by-step explanation:
To complete the square we use the formula:

So we can plug in 14 for b to find c.

Now this equation can be factored into:

Twice a number decreased by 11 is -23
Let the number be x
So we get the equation
2x -11 = -23
Add 11 to both sides
2x = -12
Divide both sides by 2
x = -6
So the number is -6
Negative 6