if a tablet has the capacity of 22 GB. and for a plain textbook one bite typically corresponds to one character and an average p
1 answer:
The tablet has a capacity of 22GB
one bite = 1 character
2000 characters = 1 bite x 2000 characters= 2000 bites
1 bite = 1 x 10^-9 giga bite
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x bite = 22 giga bite
Cross multiplying
x bite = (22GB) / 1 x 10^-9 GB
x = 2.2 x 10^10 bites
To find how many pages of text the tablet holds we divide the value of 22GB in bites by the number of bites of one page
22GB = 2.2 x 10 ^10 bites
1 page holds 2000 bites
No of pages of text the tablet can hold = (2.2 x 10^10)/2000 = 11000000 pages of text
A 500 page book has 500 x 2000 characters = 1,000,000 characters
1000000 characters = 1000000 bites
The number of 500-page books the tablet can hold =
answer for the B part = 22,000 500-page books
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