Answer:
yeah physics is hard young one
Answer:
Please see attached image and all steps below for both parts
Step-by-step explanation:
Task 1
The following system of equations includes a linear equation and a quadratic one:

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]
There are two solutions: x = 0 and x = 9.
When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.
Task 2
Part 1:
Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10
So we can use:

to calculate its square.
Part 2:
let's choose a=9 and b=10 so we use:

Answer:
x = 13
Step-by-step explanation:
Step 1: Define
f(x) = (x - 1)/2
f(x) = 6
Step 2: Substitute and solve for <em>x</em>
6 = (x - 1)/2
12 = x - 1
x = 13
Answer:
<h2>
<em><u>$23.40 </u></em></h2>
Step-by-step explanation:
<em><u>Given,</u></em>
Cost price of 8 cakes = $62.40
<em><u>So,</u></em>
Cost price of 1 cake = $ 
<em><u>Therefore,</u></em>
Cost price of 3 cakes
= $(
× 3)
- <em>[On dividing 62.40 by 8]</em>
= $(7.80 × 3)
- <em>[On multiplying]</em>
= $23.40
<em><u>Hence,</u></em>
<em><u>The required cost of 3 cakes is $23.40 (Ans)</u></em>
A
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