Answer:combining like terms is technically putting values that have the same variable (letter) Or numbers together to make a more simplified equation
Step-by-step explanation:
Answer:
A, C are true . B is not true.
Step-by-step explanation:
Mean of a discrete random variable can be interpreted as the average outcome if the experiment is repeated many times. Expected value or average of the distribution is analogous to mean of the distribution.
The mean can be found using summation from nothing to nothing x times Upper P (x) , i.e ∑x•P(x).
Example : If two outcomes 100 & 50 occur with probabilities 0.5 each. Expected value (Average) (Mean) : ∑x•P(x) = (0.5)(100) + (0.5)(50) = 50 + 25 = 75
The mean may not be a possible value of the random variable.
Example : Mean of possible no.s on a die = ( 1 + 2 + 3 + 4 + 5 + 6 ) / 6 = 21/6 = 3.5, which is not a possible value of the random variable 'no. on a die'
Even # --------- if it ends with 0, # of ways = 6*5*4 = 120 if not, 3 ways for ending digit, 5 ways for 1st digit, 5*4 for middle digits = 300
so total ways = 420
odd # --------- 4 ways of ending digit, 5 ways for 1st digit, 5*4 for middle digits = 400 ways
< 4000: ---------- 3 ways for starting digit, 6*5*4 ways for remaining digits = 360 ways
> 3000 & < 4000 ------------------------ 1 way for starting digit , 6*5*4 for remaining digits = 120 ways
Answer:
Step-by-step explanation:
Let d represent the number of dimes. Then 81-d is the number of nickels and the total value in cents is ...
10d +5(81-d) = 530
5d +405 = 530 . . . eliminate parentheses
d +81 = 106 . . . . . divide by 5
d = 25 . . . . . . . . . subtract 81; number of dimes
81 -d = 81 -25 = 56 . . . . . number of nickels
There are 25 dimes and 56 nickels in the box.
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<em>Comment on the method of solution</em>
It usually works well to let the variable represent the amount of the highest-value contributor (dimes). This keeps the numbers positive as the solution progresses.
Answer:
2,225.54
Step-by-step explanation:
I am not sure if I am correct or not but it is either the first or second one.
