Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation for the amounts are given as follows:
The proportion is the <u>p-value of Z when X = 4250</u>, hence:
Z = 1.66
Z = 1.66 has a p-value of 0.9515.
Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
More can be learned about the normal distribution at brainly.com/question/15181104
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Hi there!
In order to solve, you can use substitution. This means that you use one equation and solve for one variable, then use that one equation and plug it into the other equation. Here's how we'd do it:
WORK:
x = 12 - y (since x is already solved for, we'll use that to plug into the other given equation.
2(12 - y) + 3y = 29 (using substitution)
24 - 2y + 3y = 29
24 + y = 29
y = 5
Plug the value of y back into the first equation
x = 12 - 5
x = 7
ANSWER:
A - x = 7, y = 5
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Answer:
54 cups of flour
Step-by-step explanation:
2.378 + 3.56 = 5.938
two and 378 inches = 2.378
