54.8. Hope that helped :)
Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
g(4) = 7 and f(g(4)) = 43
Step-by-step explanation:
First find g:
g(x) = 3x-5
g(x) = 3(4) - 5
g(x) = 12 - 5
g(x) = 7
Plug in:
f(g(4))
f(7)
Now, find f:
7^2 - 7 + 1
49 - 7 + 1
42 + 1
f(x) = 43
Answer:
-7
Step-by-step explanation:
30-16= -5n +3n
14 = -2n
multiplying both by half,u have -
7 = -n
multiply both by -1
7 = n
34Step-by-step explanation:
dk im so sorry