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harina [27]
3 years ago
11

How many degrees are there in 5/6 of a revolution?

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0

Answer:

\Huge \boxed{300 \° }

Step-by-step explanation:

A revolution is 360 degrees.

5/6 of a revolution is 5/6 of 360 degrees.

5/6 × 360 = 300

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KATRIN_1 [288]
Multipl .365 by 100 and you get 36.5%
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What number will fill in the blank ...... 1/3 = (blank)/6
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2

Step-by-step explanation:

1/3 = x/6

Equivalent fractions.

Multiply 3 by 2 for x

(1×2)/(3×2) = 2/6

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7. Which coordinate lies in the solution set for
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Answer:

The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.

Step-by-step explanation:

See the graph attached to this question.

The solution of the set of inequalities is given by the shaded region on the graph.

Now, the point (0,5) is outside this shaded region, hence it can not be the solution.

The point (3,0) also is outside this shaded region, hence it can not be the solution.

The point (-3,0) also is outside this shaded region, hence it can not be the solution.

Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)

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3 years ago
2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28
JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let p_1 = <u><em>proportion of deaths when drivers were not wearing seat belts.</em></u>

p_2 = <u><em>proportion of deaths when drivers were wearing seat belts.</em></u>

So, Null Hypothesis, H_0 : p_1=p_2      {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, H_A : p_1\neq p_2     {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of deaths when drivers were not wearing seat belts = \frac{31}{2823} = 0.011

\hat p_2 = sample proportion of deaths when drivers were wearing seat belts = \frac{16}{7765} = 0.002

n_1 = sample of drivers not wearing seat belts = 2823

n_2 = sample of drivers wearing seat belts = 7765

So, <u><em>the test statistics</em></u>  =  \frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }

                                       =  4.438

The value of z test statistics is 4.438.

<u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, <u>Margin of error</u> (E) =  1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }

                                        =  1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }

                                        =  <u>0.00397</u>

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3 years ago
Write a polynomial in standard form with zeros at -2 and 3 !!!!! PLZ HELP
lara31 [8.8K]

If the zeros are -2 and 3, then the factored form would be

(x+2) and (x-3)  

-2+2 = 0 and 3-3 = 0

A polynomial is written as ax^2 + bx + c

Expand (x+2) (x-3) using FOIL: Multiply each tern in one set of parenthesis by each term in the other set and then simplify by combining like terms:

x*x + x*-3 + 2*x + 2*-3

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Polynomial in standard form:

x^2 -x -6

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