Answer:
17.32m ; 110°
Step-by-step explanation:
Distance between X and Z
To calculate the distance between X and Z
y^2 = x^2 + z^2 - (2xz)*cosY
x = 20, Z = 10
y^2 = 20^2 + 10^2 - (2*20*10)* cos60°
y^2 = 400 + 100 - (400)* 0.5
y^2 = 500 - 200
y^2 = 300
y = sqrt(300)
y = 17.32m
Bearing of Z from X:
Using cosine rule :
Cos X = (y^2 + z^2 - x^2) / 2yz
Cos X = (300 + 100 - 400) / (2 * 20 '*10)
Cos X = 0 / 400
Cos X = 0
X = cos^-1 (0)
X = 90°
Bearing of Z from X
= 20° + X
= 20° + 90°
= 110°
Answer:
FG = 16
Step-by-step explanation:
if df bisects <edg then triangles DFE and DFG are similar AAA
since DF is the same in both triangles triangles DFE and DFG are congruent
therefore FE = FG
n+5 = 2n-6
subtract n from each side
n-n+5 = 2n-6-n
5 = n-6
add 6 to each side
5+6 = n
n=11
FG = 2n-6
=2*11 -6
= 22-6
= 16
4926.25965251
I used a calculator because it makes solving this much easier
Answer:
i think its A
Step-by-step explanation:
This one.
The doubly-shaded area is the solution set. The dashed line is not included.
