The two pictures are the questions and question five is what i need help with.
2 answers:
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Answer:
Container B has smaller surface area.
Step-by-step explanation:
Given:
Container A
Radius = 60/2 = 30 mm
Height = 4 x 60 = 240 mm
Container B
Length = 120
Width = 120
Height = 60
Computation:
Surface area of container A (Cylinder) = 2πr[h+r]
Surface area of container A (Cylinder) = 2[22/7][60][120+60]
Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)
Surface area of container B (Cuboid) = 2[lb+bh+hl]
Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]
Surface area of container B (Cuboid) = 57,600 mm²
Container B has smaller surface area.
