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wel
2 years ago
10

Consider the graph of function g below. A diagonal curve declines from (negative 1, 9) through (0, 6), (2, 0), (3, negative 3),

(4, negative 6), and (5, negative 9) on an x y coordinate plane. Determine which sequences of transformations could be applied to the parent function f(x) = x to obtain the graph of g. Reflect over the x-axis, vertically stretch by a factor of 3, and then shift up 6 units. Shift right 6 units, reflect over x-axis, and then vertically stretch by a factor of 3. Shift up 6 units, reflect over the x-axis, and then vertically stretch by a factor of 3. Shift right 2 units, reflect over x-axis, and then vertically stretch by a factor of 3. Reflect over the y-axis, vertically stretch by a factor of 3, and then shift up 6 units. Shift left 2 units, reflect over x-axis, and then vertically stretch by a factor of 3.

Mathematics
1 answer:
KatRina [158]2 years ago
4 0

The parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

<h3>What is geometric transformation?</h3>

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

The converted function, when compared to the original function, will be obtained as y = -2x + 6 if we plot it on the coordinate plane.

The only method by which the provided graph may be converted to the coordinates specified in the problem is;

Reflect over the y-axis, multiply the vertical stretch by two, and then move up six units.

Thus, the parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

Learn more about the geometric transformation here:

brainly.com/question/16156895

#SPJ1

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The z-score is calculated as (x - m) / s, where x is the actual score, m is the mean, and s is the standard deviation. In this case, x = 176, m = 154, and s = 9.8. Therefore z can be calculated as: z = (176 - 154) / 9.8 = 2.245, and the z-score of 2.245 means that 176 is 2.245 standard deviations above the mean.
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4 years ago
Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y &gt; a) = qa .
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Answer:

a) For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

b) P(Y>a)= q^a

P(Y>b) = q^b

So then we have this using independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

If we define the random of variable Y we know that:

Y\sim Geo (1-p)

Part a

For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

Part b

For this case we can use the result from part a to conclude that:

P(Y>a)= q^a

P(Y>b) = q^b

So then we have this assuming independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

Part c

For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

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Answer:

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Step-by-step explanation:

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3 years ago
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