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wel
1 year ago
10

Consider the graph of function g below. A diagonal curve declines from (negative 1, 9) through (0, 6), (2, 0), (3, negative 3),

(4, negative 6), and (5, negative 9) on an x y coordinate plane. Determine which sequences of transformations could be applied to the parent function f(x) = x to obtain the graph of g. Reflect over the x-axis, vertically stretch by a factor of 3, and then shift up 6 units. Shift right 6 units, reflect over x-axis, and then vertically stretch by a factor of 3. Shift up 6 units, reflect over the x-axis, and then vertically stretch by a factor of 3. Shift right 2 units, reflect over x-axis, and then vertically stretch by a factor of 3. Reflect over the y-axis, vertically stretch by a factor of 3, and then shift up 6 units. Shift left 2 units, reflect over x-axis, and then vertically stretch by a factor of 3.

Mathematics
1 answer:
KatRina [158]1 year ago
4 0

The parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

<h3>What is geometric transformation?</h3>

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

The converted function, when compared to the original function, will be obtained as y = -2x + 6 if we plot it on the coordinate plane.

The only method by which the provided graph may be converted to the coordinates specified in the problem is;

Reflect over the y-axis, multiply the vertical stretch by two, and then move up six units.

Thus, the parent function, f(x) = x, might undergo the following series of transformations to produce the graph: Reflect over the y-axis, vertical stretch by a factor of 2, and then shift up 6 units.

Learn more about the geometric transformation here:

brainly.com/question/16156895

#SPJ1

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Please help, will mark brainliest .
yan [13]

18/3=6

24/3=8

21/3=7

The missing side is 7

4 0
3 years ago
Is this a function? yes or no <br><br><br> picture included ^^^^
aliya0001 [1]

Answer:

Yes this is a function because when doing the straight line test it doesn't touch it two or more times.

8 0
2 years ago
I'm trying to find out the number of how much it cost to wrap each present, day one 41 small gifts were wrapped and 45 large wer
Licemer1 [7]

Answer:

Small gift: $2

Large gift: $7

Step-by-step explanation:

Let x represent cost of wrapping each small gift and y represent cost of wrapping each large gift.

We have been given that day one 41 small gifts were wrapped and 45 large were wrapped equaling $397.

We can represent this information in an equation as:

41x+45y=397...(1)

We are also told that day two 30 small gifts were wrapped and 47 large were wrapped equaling $389. We can represent this information in an equation as:

30x+47y=389...(2)  

From equation (1), we will get:

x=\frac{397-45y}{41}

Upon substituting this value in equation (2), we will get:

30(\frac{397-45y}{41})+47y=389

\frac{11910-1350y}{41}+\frac{47*41y}{41}=389

\frac{11910-1350y+1927y}{41}=389

\frac{11910+577y}{41}=389

\frac{11910+577y}{41}\cdot 41=389\cdot 41

11910+577y=15949

11910-11910+577y=15949-11910

577y=4039

\frac{577y}{577}=\frac{4039}{577}

y=7

Therefore, cost to wrap a large gift is $7.

Upon substituting y=7 in equation x=\frac{397-45y}{41}, we will get:

x=\frac{397-45(7)}{41}

x=\frac{397-315}{41}

x=\frac{82}{41}

x=2

Therefore, cost to wrap a small gift is $2.

8 0
2 years ago
Determine which of the lines are parallel and which of the lines are perpendicular. Select all of the statements that are true.
slega [8]

Answers:

Line A is parallel to line D.

Line A is perpendicular to line C.

Line C is perpendicular to line D.

=====================================================

Explanation:

Let's use the slope formula to calculate the slope of the line through (-1,-17) and (3,11)

(x_1,y_1) = (-1,-17) \text{ and } (x_2,y_2)  = (3,11)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{11 - (-17)}{3 - (-1)}\\\\m = \frac{11 + 17}{3 + 1}\\\\m = \frac{28}{4}\\\\m = 7\\\\

The slope of line A is 7

-------------

Now let's find the slope of line B.

(x_1,y_1) = (0,4) \text{ and } (x_2,y_2)  = (7,-5)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-5 - 4}{7 - 0}\\\\m = -\frac{9}{7}\\\\

-------------

Now onto line C.

(x_1,y_1) = (7,1) \text{ and } (x_2,y_2)  = (0,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 1}{0 - 7}\\\\m = \frac{1}{-7}\\\\m = -\frac{1}{7}\\\\

-------------

Lastly we have line D.

(x_1,y_1) = (-1,-6) \text{ and } (x_2,y_2)  = (1,8)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{8 - (-6)}{1 - (-1)}\\\\m = \frac{8 + 6}{1 + 1}\\\\m = \frac{14}{2}\\\\m = 7\\\\

------------------------------

Here's a summary of the slopes we found

\begin{array}{|c|c|} \cline{1-2}\text{Line} & \text{Slope}\\\cline{1-2}\text{A} & 7\\\cline{1-2}\text{B} & -9/7\\\cline{1-2}\text{C} & -1/7\\\cline{1-2}\text{D} & 7\\\cline{1-2}\end{array}

Recall that parallel lines have equal slopes, but different y intercepts. This fact makes Line A parallel to line D.

Lines A and C are perpendicular to one another, because the slopes 7 and -1/7 multiply to -1. In other words, -1/7 is the negative reciprocal of 7, and vice versa. These two lines form a 90 degree angle.

Lines C and D are perpendicular for the same reasoning as the previous paragraph.

Line B unfortunately is neither parallel nor perpendicular to any of the other lines mentioned.

You can use a graphing tool like Desmos or GeoGebra to verify these answers.

6 0
1 year ago
6th grade math help me pleaseeee
Furkat [3]

Answer:

I think it's the top left one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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