Personally I'd solve this inequality for y first: y < x-3.
That immediately eliminates (6,2) and (2,6).
Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?
-1 < 2 -3 NO. -1 < -1 is false. Was there a fourth answer choice?
Total = Principal * (1 + rate)^years
Total = 1,300 * (1.0475) ^ 5
Total = 1,300 *
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1.2611599139
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Total =
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1,639.5</span></span></span>1
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
Answer:
x=26
Step-by-step explanation:
The sum of the angles of a triangle add to 180 degrees
(2x-5)° +(4x-1)° + 30° = 180
Combine like terms
6x +24 =180
Subtract 24 from each side
6x+24-24 =180-24
6x = 156
Divide by 6
6x/6 =156/6
x =26