Answer:
When we have a discount of X% of the original price, the new price is calculated as:
New price = (original price) - (original price)*(X%/100%)
In our case, let's define:
P = original price of the fishing pole
f = price of the fishing pole after the discount
X% = 20%
Then the equation for the price of the fishing pole is:
f = P - P*(20%/100%) = P - P*0.2 = P*(1 - 0.2) = P*0.8
f = 0.8*P
This means that the price after the discount is 0.8 times the original price.
Answer: 0=0
Step-by-step explanation:
First you want to solve for x
2x+y=−4
Step 1: Add -y to both sides.
2x + y + −y =−4+ −y
2x=−y−4
Step 2: Divide both sides by 2.
2x/2= -y-4/2
x=-1/2y-2
Then you want to plug in your answer for x into the equation so:
2(-1/2y-2)+y=-4
Step 1: Simplify both sides of the equation.
2(-1/2y-2)+y=-4
(2)(
−1/
2
y)+(2)(−2)+y(Distribute)
−y+−4+y=−4
(−y+y)+(−4)=−4(Combine Like Terms)
−4=−4
−4=−4
Step 2: Add 4 to both sides.
−4+4=−4+4
0=0.
Sorry if this wasn't the answer your looking for. If you need more help I suggest using Ma.th.Pa.pa calculator but with out the periods. Hope you have a good day :)
Answer:
A)6x-18, B)They are not equal, since 6xx18 is not equal to 6x-9
Step-by-step explanation:
2(3x-9) = 2(3x)-2(9) =6x-18.
Answer: X is equal to 8 and Y is equal to 3
Answer:
option c) x₁₁ + x₁₂ = 8000
Step-by-step explanation:
Given:
xij = gallons of component i used in gasoline j
gallons of component 1 available = 8,000
demand gasoline types 1 = 11,000
demand gasoline types 2 = 14,000
Here, we have only component 1 available i.e i = 1 only
( therefore, all the options containing i = 2 gets eliminated )
thus,
component 1 will fulfill the demand of gasoline types 1 and 2 i.e j = 1 and 2
hence,
the equation satisfying the above conditions comes out as:
x₁₁ + x₁₂ = 8000
that means gallons of component 1 used in gasoline 1 and 2 and the total equals to the gallons of component 1 available i.e 8000
