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1 year ago

12

10x−y = 10 −2x+ 5y = −2

1 answer:

Viefleur [7K]1 year ago

5 0

Answer:

x=1 & y=0

Step-by-step explanation:

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if someone could explain how to evaluate absolute value to me I would appreciate it and maybe you could explain how to solve the

MAVERICK [17]

When calculating absolute value (like those questions above) you do whatever is in the absolute value bars first (if its just a number then.... just make the number positive, even if it is negative or already positive) and whatever answer you get inside those absolute value bars will ALWAYS be positive unless it's like -[4} then it's a negative number bcz the positive outcome that comes out of the absolute value bars gets multiplied by -1 (or just turned negative). So, for the first one you do 22+48=70 and -7--20=13 and then make the outcome of both of those positive and then subtract them from each other 70-13=57. For the second one you do 7+-33=-26 and 4+16=20 and make the outcome of both of those positive and then you add 26+20=46 and so and so on for the other problems.

6 0

4 years ago

Read 2 more answers

9x-6=180 <br> What does x equal in this equation

raketka [301]

Answer:

X=20.6666

Step-by-step explanation:

7 0

3 years ago

Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v

jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given x = 1 6 (u + v) …(i)

Differentiating equation (i) partially with respective to 'u'

$\frac{∂x}{∂u} = 16(1)+16(0)=16$

Differentiating equation (i) partially with respective to 'v'

$\frac{∂x}{∂v} = 16(0)+16(1)=16$

Differentiating equation (i) partially with respective to 'w'

$\frac{∂x}{∂w} = 0$

Given y = 1 6 (u − v) …(ii)

Differentiating equation (ii) partially with respective to 'u'

$\frac{∂y}{∂u} = 16(1) - 16(0)=16$

Differentiating equation (ii) partially with respective to 'v'

$\frac{∂y}{∂v} = 16(0) - 16(1)= - 16$

Differentiating equation (ii) partially with respective to 'w'

$\frac{∂y}{∂w} = 0$

Given z = 6uvw ..(iii)

Differentiating equation (iii) partially with respective to 'u'

$\frac{∂z}{∂u} = 6vw$

Differentiating equation (iii) partially with respective to 'v'

$\frac{∂z}{∂v} =6 u (1)w=6uw$

Differentiating equation (iii) partially with respective to 'w'

$\frac{∂z}{∂w} =6 uv(1)=6uv$

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

$\left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|$

Determinant 16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

= -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

6 0

3 years ago

Find BC<br>AC = 7<br>BD = 7.5<br>DE = 1.5<br>AE = 11

tatuchka [14]

5

CE=AE-AC=4

CD=CE-DE=4-1.5=2.5

BC=BD-CD=7.5-2.5=5

3 0

4 years ago

Greatest to least π^2/4, √4, 2.93

NemiM [27]

Answer:

2.93, √4, π^2/4

<em>Hope this helps</em>

<em>-Amelia</em>

4 0

3 years ago