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Vlada [557]
1 year ago
5

Which of the following rational expressions has the domain restrictions X = -6 and x = 1?

Mathematics
1 answer:
Tcecarenko [31]1 year ago
7 0

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression

\frac{(x+2)(x-3)}{(x-1)(x+6)}

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).

So answer is,

\frac{(x+2)(x-3)}{(x-1)(x+6)}

Option B is correct.

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Convert <span>6\frac{3}{8}<span>6<span><span>​8</span>​<span>​3</span><span>​​</span></span></span></span><span> to improper fraction. Use this rule: </span><span>a \frac{b}{c}=\frac{ac+b}{c}<span>a<span><span>​c</span>​<span>​b</span><span>​​</span></span>=<span><span>​c</span>​<span>​<span>ac+b</span></span>​​:</span></span></span>
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</span></span>Simplify <span>6\times 8<span>6×8</span></span><span> to </span>48: <span><span><span><span><span>
​</span>8</span>​<span>​<span>48+3</span></span><span>​​</span></span>−2∣+∣−8<span><span>​8</span>​<span>​5</span><span>​​</span></span>−1∣


</span>Simplify <span>48+3<span>48+3</span></span><span> to </span>51:</span><span><span><span><span><span>
​</span>8</span>​<span>​<span>51</span></span><span>​​</span></span>−2∣+∣−8<span><span>​8</span>​<span>​5</span><span>​​</span></span>−1∣

</span> Make the denominators the same:
<span><span><span>51</span><span>​​/8</span></span>−2×<span><span>​8</span>​<span>​8</span><span>​​

</span></span></span><span>Simplify. Denominators are now the same:
</span>
<span><span><span>51</span><span>​​/8</span></span>−<span><span>​8</span>​<span>​<span>16</span></span><span>​​
</span>
</span></span>Join the denominators: \frac{51-16}{8}<span><span>​8</span>​<span>​<span>51−16</span></span><span>​​
</span>
etc.. and your answer will be 14

</span></span>
3 0
3 years ago
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