Which of the following rational expressions has the domain restrictions X = -6 and x = 1?

1 answer:

7 0

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression

$\frac{(x+2)(x-3)}{(x-1)(x+6)}$

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).

So answer is,

$\frac{(x+2)(x-3)}{(x-1)(x+6)}$

Option B is correct.

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