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3 years ago

The ages of students in a community science club are 13,11,14,12,8 and 10 what is the range of ages in this club?

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

Answer:

Range = 6

Step-by-step explanation:

Lets arrange the ages in order first:

8, 10, 11, 12, 13 , 14

The range is the highest value from the set of numbers MINUS the lowest value.

The arranged number tells us that the:

Highest Value = 14

Lowest Value = 8

Thus, we can say:

Range = highest - lowest = 14 - 8 = 6

Range = 6

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Vlad1618 [11]

7) Write the decimal number as a fraction
(over 1)
2.18 = 2.18 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 2.18 × 10 × 10 × 10 = 2180
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 2180 / 1000

Simplifying our fraction

= 2180/1000

= 109/50

= 2 9/50

8) $7 ^{-5} = \frac{1}{7^{5}}$

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3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$