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denis-greek [22]
3 years ago
8

You have 17 coins and i have 16 coins, we flip all coins at the same time. if you have more heads then you win, if we have the s

ame number of heads or if you have less then i win. what's your probability of winning?
Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

I don’t know but I want to know

IrinaK [193]3 years ago
7 0

p = e*1/2 + (1-e)/2 = 1/2 which is .5

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Susan deposits $1,200 in an account that earns 8% simple interest annually.
spayn [35]

interest = principal x rate x time

interest = 1344-1200 = 144

principal = 1200

rate = 8% = .08

144 = 1200 x .08 x Time

Time = 1.5 yrs

3 0
3 years ago
I know this easy but what is 8 times 8
Contact [7]
8 times 8 would be 64. :)
8 0
3 years ago
Read 2 more answers
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
Can u pls help I don’t understand I’ll give u 15 points
Juliette [100K]

Answer: \frac{4}{3}

Step-by-step explanation:

This is a multiplication problem. You are multiplying \frac{1}{3} by 4. This also means 4 divided by 3. They are both the same.

4 0
3 years ago
Can someone help, please?
Sunny_sXe [5.5K]
You have to first mess around with the first shape, ABCD, and split that into a rectangle and a right triangle. once you do that, it's pretty painstaking, but simple.

if you look at it you can tell that EFGH is just half the size, but the same ratios and everything.

So, you would just take every perimeter measurement from ABCD, and divide it by two and then sum them together.

2.5 + 1.5 + 4.0 + 2.0 = 10
6 0
3 years ago
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