A 2.50-kg solid, uniform disk rolls without slipping across a level surface, translating at 3.75 m/s. If the disk’s radius is 0.
1 answer:
The translational & rotational kinetic energy is :
a) The translational kinetic energy of the disk across the level surface is 17.58J.
b) The rotational kinetic energy of the disk is 8.79J.
<h3>How do you find total kinetic energy with translational and rotational?</h3>- The combined translational and rotational kinetic energies of an item in motion determine its total kinetic energy. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. Total kinetic energy is 12mvCM2 plus 12I2.
- Ek=12mv2, where m is the mass (mass of the molecule, atom, or ion) and v is the velocity of its Centre of mass, is the energy associated with the movement of a chemical entity.
- There is just one distinction between rotational and translational kinetic energy: translational energy moves in a straight path, but rotational energy does not.
- When a bicycle is being ridden down a bike path, its tyre provides an illustration of both kinetic and translational kinetic energy.
Learn more about translational & rotational kinetic energy refer to :
#SPJ1
You might be interested in
As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.
So we can say
So here if temperature becomes more cool then wavelength will increase
here we know that
It means the hottest star out of all three is star 3
and coolest star is star 1
now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.
So correct answer is
it will look more like Star 1