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erica [24]
3 years ago
14

**URGENT** Now lets look at a skydiver who jumps out of a plane that has a forward velocity of 40 m/s. ignore air resistance. Af

ter 1 second, what is the skydivers downward velocity?
Physics
1 answer:
Dennis_Churaev [7]3 years ago
5 0
If there's no air resistance, then the diver keeps moving horizontally at 40 m/s, even after s/he jumps out of a perfectly good airplane.

Also, gravity ADDS 9.8 m/s of downward speed for every second the diver falls.

One second after leaving the airplane, the diver is moving horizontally at 40 m/s, and moving vertically downward at 9.8 m/s .

The question asks for the "downward velocity".  That's 9.8 m/s .


The diver's TOTAL velocity is

                       √ (40² + 9.8²)

                   =  √ (1,600 m²/s² + 96.04 m²/s²)

                   =  √ (1,696.04 m²/s²)

                   =        41.2 m/s  in some direction between
                                           straight forward and straight down.
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The time taken for him to move the bin 6.5 m is 2.30 s.

The given parameters;

  • <em>weight of the load, w = 557 N</em>
  • <em>force applied , F = 410 N</em>
  • <em>angle of force, =  15°</em>
  • <em>coefficient of kinetic friction  = 0.46</em>
  • <em>distance moved, d = 6.5 m</em>

The net horizontal force on the recycling bin is calculated as follows;

Fcos\theta - F_k = ma

where;

  • <em>m is the mass of the recycling bin</em>
  • <em />F_k<em> is the frictional force </em>

W = mg

557 = 9.8m\\\\m = \frac{557}{9.8} \\\\m = 56.84 \ kg

The net horizontal force on the recycling bin is calculated as;

Fcos \theta - F_k = ma\\\\Fcos\theta - \mu_kF_n  = ma\\\\410\times cos(15) \ - \ 0.46(557) = 56.84 a\\\\139.8 = 56.84a\\\\a = \frac{139.8}{56.84} \\\\a = 2.46 \ m/s^2

The time taken for him to move the bin 6.5 m is calculated as follows;

s = v_0t + \frac{1}{2} at^2\\\\6.5 = 0 + \frac{1}{2}  \times 2.46\times t^2\\\\6.5 = 1.23 t^2\\\\t^2 = \frac{6.5 }{1.23} \\\\t^2 = 5.285\\\\t = \sqrt{5.285} \\\\t = 2.30 \ s

Thus, the time taken for him to move the bin 6.5 m is 2.30 s.

Learn more here:brainly.com/question/21684583

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3 years ago
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Explanation:

https://educationalghana.news.blog/2021/08/09/geography-human-physical-and-practical-for-wassce-novdec-candidates/

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The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.

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3 years ago
How do I solve this step by step? I’m really confused
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Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

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Write it down.


Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

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Step #3:

Take the two sets of magnitude and direction that you wrote down

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The total magnetic field at P is the SUM of (the field due to the left wire)

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So just calculate them separately, then addum up.

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