Question

Count by ones from 368 to 500. change for a larger unit if. necessary.When counted from 368 to 500

Answer 1

The number of count by ones from 368 to 500 is $\boxed{132{\text{ one's}}}.$

Further explanation:

Given:

The numbers are 500 and 368.

Explanation:

The place values are only natural numbers.

The base ten systems represent the position of a place value.

We have to find the number of count by ones from 368 to 500.

The difference between 368 and 500 can be calculated as follows,

$\begin{aligned}{\text{Difference}}&= 500 - 368\\&= 132\\\end{aligned}$

The number 500 in base ten-system can also be represented as follows,

$\boxed{500 = 500 + 0 + 0}$

The number 368 in base ten-system can also be represented as follows,

$\boxed{368 = 300 + 60 + 8}$

The number 132 in base ten-system can also be represented as follows,

$\boxed{132 = 100 + 30 + 2}$

The number of count by ones from 368 to 500 is $\boxed{132{\text{ one's}}}.$

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Number system

Keywords: factor, factorization, polynomial, quadratic, cubic, greatest common factor, groups, multiplication, product, identities, common factor, expression, terms, grouping.

Answer 2

Answer:

$368 +100 +10 +10 +10 +1+1 = 500$

Step-by-step explanation:

We have to count from 368 to 500. Basically we have to reach from 368 to 500.

This could be similar to jumping on a number line from 368 to 500.

We could use ones, tens and hundreds to do so.

If we take a jump of 100 from 368, then,

$368 + 100 = 468$, we reach 468.

If we take a jump of three tens from 468, then,

$468 + 10 = 478\\478 + 10 =488\\488 + 10 = 498$, we reach 498.

If we take a jump of two ones, then,

$498 + 1 = 499\\499 + 1 =500$, hence, we reach 500.

Thus, we have to take 1 jump of 100, three jumps of ten and two jumps of one to reach 500 from 368.