Question

∠A=6x−18 ∘ start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 6, x, minus, 18, degrees, end color #11accd \qquad \green{\angle B} = \green{14x +38^\circ}∠B=14x+38 ∘ start color #28ae7b, angle, B, end color #28ae7b, equals, start color #28ae7b, 14, x, plus, 38, degrees, end color #28ae7b Solve for xxx and then find the measure of \blueD{\angle A}∠Astart color #11accd, angle, A, end color #11accd:

Answer 1

Using the properties of alternate angles, the value of x = 8 and ∠ A = 30

What are Alternate Angles?

A transversal that crosses two parallel lines produces alternate exterior angles. They form two pairs (four total angles) of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal.

For the given question,

∠A=6x−18

∠B=14x+38

As, both parallel lines are intersected by a transversal,

the value of angle ∠A and ∠180 - B is same as they are alternate angles,

⇒ 6x−18 = 180 - 14x - 38

⇒ 6x + 14x = 142 + 18

⇒ 20x = 160

⇒ x = 8

∠A = 6x−18

⇒ ∠ A = 30

To learn more abut alternate angles from given link

brainly.com/question/26167358

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