What are the coordinates of the vertex of y = x2 – 2x – 7?

1 answer:

6 0

Rearrange to vertex form:-

y = x^2 - 2x - 7
y = (x - 1)^2 - 1 - 7
y = (x - 1)^2 - 8

The vertex is at the coordinates (1, -8)

You might be interested in

What is the product? (x 3)(2 x minus 1) 2 x squared minus 3 2 x squared 6 x 2 x squared 5 x minus 3 2 x squared 6 x minus 3.

prohojiy [21]

The product of the function is 2x^2+ 5x - 3

We are to find the product of the functions x + 3 and 2x -1

let f(x) = x+ 3

g(x) = 2x - 1

Taking the product:

f(x)g(x) = (x+3)(2x -1)

f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)

f(x)g(x) = 2x^2 - x + 6x - 3

f(x)g(x) = 2x^2+ 5x - 3

Hence the product of the function is 2x^2+ 5x - 3

Learn more on product of functions here: brainly.com/question/25638609

5 0

2 years ago

M×10-m×2=8 fill in the blanks as m

son4ous [18]

M*10-m*2=8
10m-2m=8
8m=8
Divide both sides by 8:
m=8

Fill in the m's:
1*10-1*2=8
10-2=8
8=8

Hope this helps :)

5 0

3 years ago

Given y=-3/4x-2. What is the equation of the line that is perpendicular and has the point (-4,1)? Write answer in slope intercep

raketka [301]

Answer:

y=4/3+19/3

Step-by-step explanation:

When it asks for perpendicular it means your focusing on the slope.

Perpendicular means opposite of the current slope, so flip it and change the sign (-3/4 changes to 4/3). Next you will use the equation (y-y1)=m(x-x1)

y1=the y value given

x1=the x value given

m=your slope

(y-1)=4/3(x+4) Since the x point is minus a negative we get to change the sign to a positive. Next distribute the 4/3 to each term in the parenthesis.

y-1=4/3(x)+4/3(4)

y-1=4/3x+16/3 Now we add the one to both sides.

+1 +1 The one isn't in teh correct format to just add so first imagine it as 1/1. Now to get the bottom to have a 3 like in 16/3 we just multiply the top and bottom by 3.

$\frac{1}{1} x\frac{3}{3}=\frac{3}{3}$ Now we can add this to the 16/3