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MrRissso [65]
3 years ago
8

I want answer please

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

B works it satisfies the equation to both 1 ⅔ i = 1 ⅔ i

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Pls help! I don’t understand bc I’m not smart-
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Answer:

78.5 m²

Step-by-step explanation:

The formula to find the area of a quarter of a circle: \frac{1}{4} * \pi * r^{2}, where r is the radius (diameter ÷ 2) and the \pi is alterable.

1) Substitute the given values into the formula.

= \frac{1}{4} * 3.14 * 10^{2}

2) Solve it.

= \frac{1}{4} * 314

= 78.5

3) Round it off to the nearest tenth. In this case, it has already been rounded off.

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Step-by-step explanation:

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use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11
Evgen [1.6K]
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}

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3 years ago
I need help finding the missing measure
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Answer:

i cant see the picture

Step-by-step explanation:

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