2x² - 128
2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]
2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)
An equation is:
2(x+3)-7=9
Distribute the 2
2(x)+2(3) -7=9
2x+6-7=9
Combine like terms
2x-1=9
Add one to both sides
2x-1+1=9+1
2x=10
Divide both sides by two to isolate the variable.
2x/2=10/2
x=m
Answer:
see explanation
Step-by-step explanation:
The y- intercept is at (0, 6) ⇒ c = 6
The x- coordinate of the vertex is at the midpoint of the zeros, that is
m =
=
= - 2
Since the zeros are x = - 3 and x = - 1 then the factors are (x + 3), (x + 1) and
f(x) = a(x + 3)(x + 1) = a(x² + 4x + 3)
Comparing with f(x) = ax² + 8x + 6 ⇒ a = 2
Thus
f(x) = 2x² + 8x + 6
Substitute m = - 2 into the equation for value of n
n = 2(- 2)² + 8(- 2) + 6 = 8 - 16 + 6 = - 2
Hence
c = 6, m = - 2, a = 2, n = - 2
Answer:
2.52
Step-by-step explanation:
21*.12=
2.52