Answer:
Ayush's route is 700 meters or 0.7 km longer than Sumit's route.
Step-by-step explanation:
We have been given that Ayush and Sumit take two different routes to school. Ayush's route is 1 km 2 hm long while Sumit's route is 2 hm 30 dam long.
First of all, we will convert each of our given distances into meters.
Since 500 meters is less than 1200 meters, therefore, Ayush's route is longer.
Let us find the difference between both routes as:
Therefore, Ayush's route is 700 meters longer that is equal to .
Ayush's route is 0.7 km or 700m longer than Sumit route.
Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.
We know that,
1 km = 10 hm
1 dam = 0.1 hm
Using these conversions we get
Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm
Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm
Ayush's route is longer.
Difference = 12 hm - 5 hm = 7 hm = 0.7 km [1 km = 10 hm]
Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.
See the attached picture:
Try sketching an image of the rectangle. Area = length x width. To find the perimeter you would add up the length of all four sides.
Ed's answer of is correct because he divided by to get his answer.
To solve for m in you want to isolate m by dividing by on both sides, therefore he divided by to get his answer of , and his answer is correct.