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CaHeK987 [17]
1 year ago
15

How do I answer this and can you explain it to me

Mathematics
1 answer:
11111nata11111 [884]1 year ago
7 0

Since the diagonals of a parallelogram bisect each other, it follows that:

WM=\frac{1}{2}(WY)WM\text{ =}\frac{1}{2}\times8=4

The correct answer is 4cm

You might be interested in
(7.5)What is the value of x?
koban [17]

Answer:

D 5

Step-by-step explanation:

the same scaling factor s applies to all sides when transforming from the small to the large triangle.

x×s = x + 5

(x-2)×s = x +1

=> s = (x+5)/x

=> (x-2)×(x+5)/x = x + 1

=> x² + 3x - 10 = x² + x

=> 3x - 10 = x

=> 2x = 10

=> x = 5

6 0
3 years ago
Pls answer this question
eimsori [14]

Answer:

1) B

Step-by-step explanation:

1)

The formula for the volume of a prism is h * l * w

So, if we do that we get 25/18

2) B

Lets say we talk the top surface, there are 30 cubes on that surface and we want to find the volume of one cube so we are going to divide by 50. we take the measurements which are 5/6 and 1 for the top surface and we multiply. We get an answer of 5/6 now we divide by 30

So...

5/6 * 1/30 (We switched the numbers around because we are dividing.)

5/6 * 1/30 = 5/180 now we can simplify this to 1/36.

5 and 180 are a factor of 5

Hope this helps

8 0
3 years ago
Which function represents the quadratic function f(x) = x^2 after a vertical stretch by a factor of number 2?
Zielflug [23.3K]
C is your answer. The coefficient on the x value is always a stretch factor.
3 0
2 years ago
Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .
kogti [31]

Answer:

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if (x+y)^{2} = x^{2} + 2\cdot x\cdot y  + y^{2}. From statement, we must fulfill the following identity:

a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}

By Associative and Commutative properties, we can reorganize the expression as follows:

a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2} (1)

Then, we have the following system of equations:

x = a (2)

(b^{2}-1) = 2\cdot x\cdot y (3)

y = c (4)

By (2) and (4) in (3), we have the following expression:

(b^{2} - 1) = 2\cdot a \cdot c

b^{2} = 1 + 2\cdot a \cdot c

b = \sqrt{1 + 2\cdot a\cdot c}

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, a, b, c > 1. If a, b and c are prime numbers, then  2\cdot a\cdot c must be an even composite number, which means that a and c can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, b must be a natural number, which means that:

1 + 2\cdot a\cdot c \ge 4

2\cdot a \cdot c \ge 3

a\cdot c \ge \frac{3}{2}

But the lowest possible product made by two prime numbers is 2^{2} = 4. Hence, a\cdot c \ge 4.

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Example: a = 2, c = 2

b = \sqrt{1 + 2\cdot (2)\cdot (2)}

b = 3

4 0
3 years ago
Seled the two inequalities shown in the system<br> (125 Points)
jeka94

Answer:

I am not smart enough for that one

Step-by-step explanation:

because I am just built the same as you all

6 0
3 years ago
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