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Nutka1998 [239]
1 year ago
9

Identify the homogeneous mixture among the following:

Chemistry
1 answer:
katen-ka-za [31]1 year ago
4 0
Answer: air

Explanation:since individual components of air cannot be identified by merely looking at it, it is a homogeneous mixture.
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An unknown element X has the following isotopes: ⁵²X (89.00% abundant), ⁴⁹X (8.00% abundant), ⁵⁰X (3.00% abundant). What is the
Vlad [161]

Answer:

52 amu

Explanation:

To get the relative atomic mass of the element, we need to take into consideration, the atomic masses of the different isotopes and their relative abundances. We simply multiply the percentages with the masses. This can be obtained as follows:

[89/100 * 52] + [8/100 * 49] + [3/100 * 50]

46.28 + 3.92 + 1.5 =51.7 amu

The approximate atomic mass of element x is 52 amu

6 0
3 years ago
Boreal forests are characterized by _______ trees. A. Creosote b. Eucalyptus c. Coniferous d. Deciduous Please select the best a
Aleonysh [2.5K]

Answer:

c

Explanation:

coniferous trees, Tianga also called Boreal forest biome (major life zone).

hope it's perfect.

3 0
3 years ago
Read 2 more answers
Consider the motion diagram. It illustrates a car's velocity (V) and acceleration (A). The BEST description of a car’s velocity
Masja [62]

Answer:

wheres the diagram ?

Explanation:

4 0
3 years ago
Read 2 more answers
What is the percent yield for a reaction if the theoretical yield of c6h12 is 21g and the actual yield recovered is only 3.8g?
svp [43]

Answer:

18.095 %.

Explanation:Theoretical yield is the yield calculated from the balanced chemical equation. In this reaction theoretical yield is 21g. Actual yield = 3.8g. Hence, the percent yield for this reaction is 18.095 %.

4 0
3 years ago
Suppose of lead(II) acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of acetate a
Lynna [10]

Answer:

0.294 M

Explanation:

The computation of the final molarity of acetate anion is shown below:-

Lead acetate = Pb(OAc)2

Lead acetate involves two acetate ion.

14.3 gm lead acetate = Mass ÷ Molar mass

= 14.3 g ÷ 325.29 g/mol

= 0.044 mole

Volume of solution = 300 ml.

then

Molarity of lead is

= 0.044 × 1,000 ÷ 300

= 0.147 M

Therefore the molarity of acetate anion is

= 2 × 0.147

= 0.294 M

3 0
4 years ago
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