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sukhopar [10]
3 years ago
5

The combustion of magnesium creates so much energy so quickly that it is hard to measure its enthalpy directly using a simple ca

lorimeter. However, you will break this reaction down into other intermediate reactions whose enthalpies you can – and will – measure. What broad question are you answering by doing this experiment?
Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
6 0
I believe your answer is: What is the enthalpy of formation of magnesium oxide?
Hope this helps! :)
QveST [7]3 years ago
5 0

Answer:  Enthalpy of the reaction of combustion of magnesium

Explanation: The enthalpy of reaction of combustion of methane is usually determined by the usage of the Hess law .

Hess Law states that regardless of the multiple steps of the reaction, the total enthalpy change is equal to the sum of the enthalpies of all the steps involved.

Thus in order to find out the total change in enthalpy of magnesium oxide , we can break the reaction into several intermediate reactions whose entalpies can be easily determined.

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Given that hclo4 is a strong acid, how would you classify the basicity of clo−4?
Mandarinka [93]
As a conjugate base of a strong acid,ClO4-would be classified as having a negligible basicity. The basicity of a chemical species is normally expressed by the acidity of the conjugate acid. The basicity of an acid is the number of hydrogen ions, which can be produced by one molecule of the acid. 
8 0
3 years ago
What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?
brilliants [131]

Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1      :     2           1 : 1

1 mole of Cu  = 63.5 g

1 mole of  H2 = 2g

1 mole  Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from =  (63.5/2)*10 = 317 g of Copper

4 0
3 years ago
If 5 grams of hydrogen reacted with 40 games of oxygen to form water, how much of water would be formed?
GREYUIT [131]
2H₂ + O₂ = 2H₂O

n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol

n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol

H₂ : O₂ = 2 : 1

2.5 : 1.25 = 2 : 1

n(H₂O)=n(H₂)=2n(O₂)=2.5 mol

m(H₂O)=n(H₂O)M(H₂O)

m(H₂O)=2.5mol*18.0g/mol=45.0 g
3 0
3 years ago
Balance this equation<br><br>PB3 O4 + H2 → PB + H2O​
Anna35 [415]

Answer:

Pb3O4 + 4H2 → 3Pb + 4H2O

Explanation:

Pb3O4

Tritium - H2

Molar Mass of H2 Bond Polarity H-3 Hydrogen-3 3H T

Products

Lead - Pb

Molar Mass of Pb Plumbum Element 82 Bulk Lead

Water - H2O

Molar Mass of H2O Oxidation Numbers of H2O Dihydrogen Monoxide Dihydridooxygen Hoh Hydrogen Hydroxide Dihydrogen Oxide Oxidane Hydrogen Oxide Pure Water

 

4 0
3 years ago
cylinder contains 250 g of Helium at 200 K. The external pressure is constant at 1 atm. The temperature of the surroundings is l
brilliants [131]

Answer:

The system gains 126100 J

Explanation:

The heat can be calculated by the equation:

Q = nxCxΔT, where Q is the heat, C is the heat capacity,n is the number of moles and ΔT is the variation of temperature (final - initial). The number of moles is the mass divided by the molar mass, so:

n = 250/4 = 62.5 mol.

The system must be in thermal equilibrium with the surroundings, so if the temperature of the surroundings decreased 97 K, the temperature of the system increased by 97 K, so ΔT = 97 K

Q = 62.5x20.8x97

Q = 126100 J

6 0
3 years ago
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