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sukhopar [10]
3 years ago
5

The combustion of magnesium creates so much energy so quickly that it is hard to measure its enthalpy directly using a simple ca

lorimeter. However, you will break this reaction down into other intermediate reactions whose enthalpies you can – and will – measure. What broad question are you answering by doing this experiment?
Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
6 0
I believe your answer is: What is the enthalpy of formation of magnesium oxide?
Hope this helps! :)
QveST [7]3 years ago
5 0

Answer:  Enthalpy of the reaction of combustion of magnesium

Explanation: The enthalpy of reaction of combustion of methane is usually determined by the usage of the Hess law .

Hess Law states that regardless of the multiple steps of the reaction, the total enthalpy change is equal to the sum of the enthalpies of all the steps involved.

Thus in order to find out the total change in enthalpy of magnesium oxide , we can break the reaction into several intermediate reactions whose entalpies can be easily determined.

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212 pb 82 is the isotope notation for iron. what is the atomic number, mass number, and number of both protons and neutrons?
o-na [289]

Hello!

The mass number in isotope notation is denoted A, the atomic number is denoted as Z, and the element is denoted as X.

In the given isotope, the mass of the isotope is 212 amu, and the atomic number is 82.

We know that the number of electrons, and protons are equal to the atomic number. Therefore, there are 82 protons. Also, to find the number of neutrons, we subtract the atomic number from the atomic mass.

212 - 82 = 130 neutrons

<u>Final answers</u>:  

  1. Atomic Number: 82
  2. Mass number: 212
  3. Number of Protons: 82
  4. Number of Neutrons: 130
5 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
A reaction that breaks large molecules into smaller ones by the addition of water is called a(n):
Luda [366]
Answer:  "condensation reaction" .
__________________________________________________
5 0
3 years ago
Lee and some other students working with Dr. Yung were conducting an experiment and ended up with some confusing results. In the
Alinara [238K]

Answer:

chung long

Explanation:

cause 3 plus 2 =9

6 0
3 years ago
Read 2 more answers
1. Rank the following solutions in order of increasing
babunello [35]

The order of the solutions from lowest to highest concentration : A, B, C

<h3>Further explanation</h3>

Given

the following solutions

Required

order of increasing  concentration

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Solution A : 0.5 moles : 2 L solution = 0.25 M

Solution B : 1 moles : 3 L solution = 0.33 M

Solution C : 1.5 moles : 4 L solution = 0.375 M

8 0
3 years ago
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