The reaction is missing and it's ;
N2H4 + H2 ---> 2NH3
It asks for the total pressure too.
Answer:
A) Rate of change for NH3 = 152 torr/h
B) The total pressure in the vessel will remain the same.
Step-by-step explanation:
N2H4 + H2 ---> 2NH3
1 mole of N2H4 yields 2 moles of NH3.
From the question, the rate given for N2H4 is 76 torr/h.
Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h
Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.
While on the product side, 2 moles of NH3 are produced.
So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.
M<GJI=(x+60)°=?
We need to find x. The angle GJI and FJH are opposite by the the vertex, then they must be congruents:
(x+60)°=(5x)°
x+60=5x
Solving for x
x+60-x=5x-x
60=4x
60/4=4x/4
15=x
x=15
Replacing x by 15 in m<GJI:
m<GJI=(x+60)°=(15+60)°→m<GJI=75°
Answer: Option b. 75
3/8+4/8=7/8
It moves 3/8 first, then 4/8.
Answer:
E=(-1,3) F= (3,3) G=(-2,-1) H=(4,-1)
the shape is a trapizode