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Kitty [74]
3 years ago
8

How many arrangements of three flowers are there if there are 6 types to choose from

Mathematics
1 answer:
shutvik [7]3 years ago
8 0
There are 20 possible combinations I believe.
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Can you help me with my algebra
Over [174]
Sure. Can u show the question or somthing and I got u fam
7 0
3 years ago
Find the output of the function machine<br>9 √<br><br>​
Afina-wow [57]

Answer:

3

Step-by-step explanation:

Assuming a typo in your question. Sqrt(9) = 3

5 0
3 years ago
Help pls and quick thanks
storchak [24]

Answer:

I think the Question asks to to take w in left side. so, the answer is below

Step-by-step explanation:

w=sa

5 0
2 years ago
Complete the equation of variation where y varies inversely as x and y = 80 when x = 0.7.
andre [41]
Y varies inversely with x
means that y=k/x 
with x=0.7 and y=80
we have 80=k/0.7
k=0.7x80=56
so the equation is 
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3 0
3 years ago
Read 2 more answers
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0
3 years ago
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