Question

What are the first nine multiples of 5, and 3?

Answer 1

First 9 multiples of 5:

$\begin{gathered} 5\cdot1=5 \\ 5\cdot2=10 \\ 5\cdot3=15 \\ 5\cdot4=20 \\ 5\cdot5=25 \\ 5\cdot6=30 \\ 5\cdot7=35 \\ 5\cdot8=40 \\ 5\cdot9=45 \end{gathered}$

First 9 multiples of 3:

$\begin{gathered} 3\cdot1=3 \\ 3\cdot2=6 \\ 3\cdot3=9 \\ 3\cdot4=12 \\ 3\cdot5=15 \\ 3\cdot6=18 \\ 3\cdot7=21 \\ 3\cdot8=24 \\ 3\cdot9=27 \end{gathered}$