I got 0.55 when I did this problem. If I am wrong I am so sorry and please correct me.
Answer:
BAF and FAD
Step-by-step explanation:
In order for an angle to have A.F as a side, it must have the letters A.F or FA in its name.
In DAF, the angle is made of rays AD and A.F. In DAB, the angle is made up of rays AD and AB. This is not the correct pair.
In EAF, the angle is made of rays AE and A.F. In CAE, the angle is made up of rays AC and AE. This is not the correct pair.
In BAF, the angle is made of rays AB and A.F. In EAD, the angle is made up of rays AE and AD. This is not the correct pair.
In BAF, the angle is made up of rays AB and A.F. In FAD, the angle is made up of rays A.F and AD. This is the correct pair.
Ithe diameter would be about 5
Answer:
n squared + 3n + 1
Step-by-step explanation:
5,11,19,29
Firstly look at the difference between each number. The first difference is 6 then 8 then 10 etc. After that you look at your created sequence - 6,8,10 etc. The difference is 2 each time. Then applying rules, you have to do the constant difference divided by 2 to get a coefficient of n squared. So in this case it's n squared because 2/2 = 1 so you don't have to place a 1 in front of the n squared. After you create a sequence from the n squared. That would be 1,4,9 etc. Then you need to see how to get from the sequence: 1,4,9 etc to your original sequence: 5,11,19 etc. So if you calculate it you will get 4,7,10 because firstly 5-1 = 4 then 11-4 = 7 etc. The sequence 4,7,10 is a linear sequence so the constant difference is 3 each time. So to get a nth term of a linear sequence you will start off as 3n then you will substitute 1 then 2 then 3 into the 3n. Therefore that would be 3,6 etc. So if you take the first substituted term, that would be 3 as said before then you will have to see how to get from the 3 to 4 so that is just adding 1. So the nth term of this linear sequence is 3n + 1. Check if it works at the end. So the overall nth term of the quadratic sequence is n squared as said before + 3n + 1.