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Iteru [2.4K]
3 years ago
5

I will use fancy gold and red wrapping paper for two packages i have to wrap. I will use 1 2/4 yard of paper for one of the boxe

s and 5/6 for the other box.The paper must be cut into pieces that are 1/3 yard long. How many pieces will i cut to use for the gift boxes.
Mathematics
1 answer:
Allisa [31]3 years ago
6 0
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.

You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
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3 years ago
A data set is summarized in the frequency table below. Using the table, determine the number of values less than or equal to 6.
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Answer:

18

Step-by-step explanation:

Given the above table of the data set, the number of values less than or equal to 6 would be the sum of the frequencies of all values that is equal to or less than 6.

From the table above, we would add up the frequencies of the values of 6 and below, which is:

2 + 3 + 6 + 4 + 3 = 18

Answer = 18

8 0
3 years ago
Does anyone know the answer?
motikmotik

Answer:

We conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

  • Base = p+1
  • Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

                                            =\frac{1}{2}\left(p+1\right)\left(2p-6\right)

Factor 2p-6: 2(p-3)

                                             =\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}  

Divide the number: 2/2 = 1

                                              =\left(p+1\right)\left(p-3\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

                                               =pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)

                                               =pp-3p+1\cdot \:p-1\cdot \:3

                                                =p^2-2p-3

Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

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Answer:

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Step-by-step explanation:

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