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Iteru [2.4K]
3 years ago
5

I will use fancy gold and red wrapping paper for two packages i have to wrap. I will use 1 2/4 yard of paper for one of the boxe

s and 5/6 for the other box.The paper must be cut into pieces that are 1/3 yard long. How many pieces will i cut to use for the gift boxes.
Mathematics
1 answer:
Allisa [31]3 years ago
6 0
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.

You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
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What would the first step be in solving the inequality: -y (less than or greater than sign) 136
Alex73 [517]

"-y (less than or greater than sign) 136" translates into two separate inequalities:


-y < 136 and -y > 136.


You want to solve for y in each case. To do this, multiply each inequality by "-1" and then immediately change the direction of the inequality sign.


For example: -1(-y < 136) => y > -136.

5 0
3 years ago
I don’t understand this can someone help it’s a practice test please show steps.
fomenos

Using the sinusoidal function, it is found that the temperature will be below 0ºC between May and August.

<h3>What is a Sinusoidal function?</h3>
  • A sinusoidal function is a function that depends on a trigonometric function, having peaks according to the period and amplitude given by this function.

The function for the average monthly temperature, in m months after January, is given by:

T(m) = 10\cos{\left(\frac{\pi}{6}\right)m} + 5

Working with elementary angles, we have that:

m = 10, T(0) = 10\cos{0} + 5 = 15

m = 3, T(3) = 10\cos{\left(\frac{\pi}{2}\right)} + 5 = 5

m = 6, T(3) = 10\cos{\pi} + 5 = -5

m = 9, T(3) = 10\cos{\left(\frac{3\pi}{2}\right)} + 5 = 5

m = 12, T(3) = 10\cos{2\pi} + 5 = 5

From this, we have that it becomes negative after March, and positive before September, removing the middle two options.

Now, we have to test for April and May, that is, m = 4 and m = 5, hence:

m = 4, T(4) = 10\cos{\left(\frac{2\pi}{3}\right)} + 5 = 0

m = 5, T(5) = 10\cos{\left(\frac{5\pi}{6}\right)} + 5 = -3.66

Negative only in May, hence the temperature will be below 0ºC between May and August.

To learn more about sinusoidal function, you can take a look at brainly.com/question/18055768

7 0
2 years ago
Evaluate the expression 2×2×2[1/4+4(36÷12)]
frez [133]
2*2*2[\frac{1}{4}+4(36:12)]=8(\frac{1}{4}+4*3)=8*(\frac{1}{4}+12)=8*12,25=98
3 0
3 years ago
Find rules for quadratic functions with graphs meeting these conditions.
Elena L [17]
1.) (x - 4)(x + 1) = 0
x^2 + x - 4x - 4 = 0
y = x^2 - 3x - 4

2.) (x - 2)(x - 6) = 0
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x^2 - 8x + 12 = 0
since the function has a maximum point the leading coefficient is negative.
Therefore, required equation is y = -3x^2 + 24x - 36

3.) a(x + 3)^2 = ax^2 + 6ax + 9a
since the y intercept is at y = 18 => 9a = 18 => a = 2
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3 years ago
while playing mini golf, you hit the ball off of a wall to attempt at making it into the hole. The ball is located (5,4) and the
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9 times 4 equal 36 and 5 times 8 equals 40 
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