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Iteru [2.4K]
3 years ago
5

I will use fancy gold and red wrapping paper for two packages i have to wrap. I will use 1 2/4 yard of paper for one of the boxe

s and 5/6 for the other box.The paper must be cut into pieces that are 1/3 yard long. How many pieces will i cut to use for the gift boxes.
Mathematics
1 answer:
Allisa [31]3 years ago
6 0
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.

You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
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antoniya [11.8K]

Answer:

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Explanation:

3 3/2

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3 years ago
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2x +4 (3 - 2x) = 3(2x + 2)/6 + 4<br> from my math book
liberstina [14]

Answer:

x = 1

Step-by-step explanation:

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4 0
2 years ago
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Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts
nignag [31]

Answer:

30 + 0.05x < 60

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

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So, for x tests, the charge is:

C(x) = 30 + 0.05x

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

C(x) < 60

30 + 0.05x < 60

The solution is:

0.05x < 30

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The number of texts she can have is less than 600.

5 0
3 years ago
Please show me how u got theses Answer
musickatia [10]

Answer:

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2 years ago
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