ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
Answer:
d
Step-by-step explanation:
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Answer:
The correct answer is D) y + 1 = -2(x - 5)
Step-by-step explanation:
All equations can be written in the following point-slope form.
y - y1 = m(x - x1)
In which, m is the slope. (x1, y1) is the given point. If we use the information given we can find the equation.
y - - 1 = -2(x - 5)
y + 1 = -2(x - 5)
It has line symmetry and rotational symmetry, so A is the answer, hope this helps
