Answer:
The sum of three consecutive integers for 198 are <em>65, 66, and 67</em>
Definition of "INTEGERS"
1. a whole number; a number that is not a fraction.
2. a thing complete in itself.
Step-by-step explanation:
198 = x + x + 1 + <em>x + 2</em>
combine like numbers
198 = 3x + 3
subtract 3 from like numbers (in this case)
198 - 3 = 3x + 3 - 3
195 = 3x
divide by 3
195/3 = 3x/3
65 = x
x + 1 = 65 + 1 ---66
x + 2 = 65 +2 --67
Answer:
f=1
Step-by-step explanation:
Let start off with doing -f plus 4f which gives you 3f. The equation would now be 2+3f=8-3f. Add 3f so you can cancel out the -3f and add the 3f to the other 3f. Now your equation is 2+6f=8. Cancel out do by doing -2. (Don't forget to to it to the 8 also.) Now your equation is 6f=6. Divide 6 from both sides to get 1. (You divide because you want to get f alone.
Good evening.
This is a
incomplete quadratic equation, because it does not have the term
bx. Therefore, we can solve this faster with the following strategy:

Add
16 to both sides:

Take the square root:

Therefore:
2. it can't have three because one of them is a right triangle do D doesn't add up. It can't have 0 because an obtuse angle plus a right angle would go over 180 degrees. So, the most it can have is 2 acute for example 90(right angle) 30(acute) and 60 (acute) is a possible answer. Also, a right angle can only have two acute angles since an obtuse angle would put it over 180 which was already stated
Step-by-step explanation:
https://youtu.be/e7WGZHTZm0I