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Anestetic [448]
1 year ago
6

A rectangle has dimensions of 9 in. by 8 in. Find the exact volume (in cubic inches) of the solid of revolution formed when the

rectangle is rotated about its 8 in. side.Incorrect: Your answer is incorrect.in3

Mathematics
1 answer:
Sauron [17]1 year ago
4 0

V = 162π in^3

Explanation:

Since rotation a rectangle on its side result to a cylinder.

We'll use the formula for the volume of a cylinder with 8in being the height (since the rectangle is rotated around that side) and 9 in as the diameter.

Data:

Radius : r = diameter / 2 = 9/2 = 4.5 in

Height : h = 8 in

Formula:

V=\pi *r^2*h

Solution:

\begin{gathered} V=\pi *4.5^2*8 \\ V=162\pi\text{ }in^3 \end{gathered}

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The sum of three consecutive integers is 198. What are the​ integers?
-BARSIC- [3]

Answer:

The sum of three consecutive integers for 198 are <em>65, 66, and 67</em>

Definition of "INTEGERS"

1.  a whole number; a number that is not a fraction.

2. a thing complete in itself.

Step-by-step explanation:

198 = x + x + 1 + <em>x + 2</em>

combine like numbers

198 = 3x + 3

subtract 3 from like numbers (in this case)

198 - 3 = 3x + 3 - 3

195 = 3x

divide by 3

195/3 = 3x/3

65 = x

x + 1 = 65 + 1  ---66

x + 2 = 65 +2  --67

6 0
3 years ago
Solve for f<br> -f +2 + 4f = 8 - 3f
Ulleksa [173]

Answer:

f=1

Step-by-step explanation:

Let start off with doing -f plus 4f which gives you 3f. The equation would now be 2+3f=8-3f. Add 3f so you can cancel out the -3f and add the 3f to the other 3f. Now your equation is 2+6f=8. Cancel out do by doing -2. (Don't forget to to it to the 8 also.) Now your equation is 6f=6. Divide 6 from both sides to get 1. (You divide because you want to get f alone.

4 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
4 0
3 years ago
Question 6 of 10 Multiple Choice: Please select the best answer and click "submit." What is the greatest number of acute angles
gavmur [86]
2. it can't have three because one of them is a right triangle do D doesn't add up. It can't have 0 because an obtuse angle plus a right angle would go over 180 degrees. So, the most it can have is 2 acute for example 90(right angle) 30(acute) and 60 (acute) is a possible answer. Also, a right angle can only have two acute angles since an obtuse angle would put it over 180 which was already stated
3 0
3 years ago
Factor the following: 28 W + 12J
muminat

Step-by-step explanation:

https://youtu.be/e7WGZHTZm0I

6 0
2 years ago
Read 2 more answers
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