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3 years ago

I need all the answers please asap

Mathematics

1 answer:

olganol [36]3 years ago

6 0

5. they give dimes of 2 identical sides 25 & 5

25/5 = 5 so ABC is 5 times larger so 12 x 5 = 60

6. V= L x W x H/3 = 6.2 x 4.5 x 5.3 = 147.87/3 = 49.29 cubic cm

7 add both losses 3 and a half + 3 and a half = 728 and a half - 7 = 21 and a half

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What's worth more a 100 dollars or 350 quarters?

Ronch [10]

Maybe 200 dollars, 500 dollars and so on

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3 years ago

The cost of the fruit is given by the function y= 3x+1, where x is the number of fruits and y is the total cost. Find the

Elza [17]

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8 0

2 years ago

PYTHAGOREAN THEOREM IN 3D URGENT PLEASE PHOTO INSERTED

Andrews [41]

To find the length of the diagonal, we need to calculate the length of the base first and then use the value to calculate the diagonal since we are given the value of height of the triangle.

<h3>Pythagorean Theorem</h3>

This theorem is used to find the missing side of a right angle triangle given that we have the length of two sides.

To calculate the base of the triangle, let's use Pythagorean theorem here

$x^2 = y^2 + z^2\\x^2 = 2^2 + 3^2\\x^2 = 4 + 9 \\x^2 = 13\\x = \sqrt{13} \\x = 3.61$

Having the length of the base, let's consider the height of the triangle which is 6 and substitute the values.

$d^2 = 6^2 + 3.61^2\\d^2 = 36 + 13.0321\\d^2 = 49.0321\\d = \sqrt{49.0321} \\d = 7.00$

From the calculations above, the values of the triangle are

diagonal = 7
base = 3.61
height = 6

Learn more on pythagorean theorem here;

brainly.com/question/231802

#SPJ1

7 0

2 years ago

Help please ASAP!!!!!<br> you can zoom in to see better

meriva

Answer:

true, false, and false

Step-by-step explanation:

6 0

3 years ago

in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

4 0

3 years ago