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Lapatulllka [165]
2 years ago
8

What force was applied to an object if 35 j of work was done and the object moved 7 m?

Chemistry
1 answer:
Serjik [45]2 years ago
8 0

5N force was applied to an object if 35 j of work was done and the object moved 7 m

A force is an effect that can alter an object motion according to physics and an object with mass can change its velocity or accelerate as a result force and also force is as push or pull and work done by the force on an object means assuming that direction of the force is parallel to the displacement of the object

Then the formula is

W = f × d

Where f is the magnitude of force and d is the displacement of the object

Then W = 35 J is the work done and

d = 7m is the displacement of the object

So rearrange the equation then

F = 35/7 = 5N

5N force was applied to an object if 35 j of work was done and the object moved 7 m

Know more about object

brainly.com/question/11748734

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Answer:

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Explanation:

Equilibrium constant of the reaction = K_c=5.10\times 10^{-6}

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     NH_4HCl(s)\rightleftharpoons 2 NH_3(g) + HCl(g)

Initial:            0.573     0           0

At eq'm:      (0.573-x)   x           x

We are given:

[NH_4Cl]_{eq}=(0.573-x)

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Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}

Putting values in above equation, we get:

5.10\times 10^{-6}=\frac{x\times x}{(0.573-x)}

2.9223\times 10^{-6}-5.10x\times 10^{-6}=x^2

x^2-2.9223\times 10^{-6}+(5.10\times 10^{-6})x=0

On solving this quadratic equation we get:

x = 0.01707 M

The equilibrium concentration of HCl is 0.01707 M.

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