Answer:
The amount of positive charge in a barium nucleus is approximately 8.972 × 10⁻¹⁸ coulomb
Explanation:
The amount of positive charge there is in a barium nucleus is found as follows;
The atomic number of an element is equal to the number of proton present in the atom
The atomic number of barium = 56 = The number of protons in an atom of barium
The positive charge of a single proton is known as an elementary charge, e, given by the formula, e = F/N
Where;
F = Faraday's constant
N = The Avogadro's number
Therefore, e = 1.602 176 634 × 10⁻¹⁹ C
Which gives the positive charge, Q, of the protons of a barium nucleus as follows;
Q = Number of protons × e
Q = 1.602176634 × 10⁻¹⁹ × 56 ≈ 8.972 × 10⁻¹⁸ Coulomb per atom of barium.
The amount of positive charge in a barium nucleus ≈ 8.972 × 10⁻¹⁸ coulomb.
Answer:
<h2>A. The image shows Boyle's Law because volume decreases as pressure increases.</h2>
Explanation:
According to Boyle's Law, at constant temperature, pressure and volume have inverse relation that is as pressure would increase, volume would decrease.
According to Charles Law, at constant pressure, the volume is directly proportional to temperature.
According to the given graph and diagram, the temperature is constant and volume and pressure have inverse relation.
Thus, option A is correct.
Answer
Manual samplers are prone to effects of temperature, speed of wind and air concentrations.
Explanation
Manual samplers face several challenges that can act as drawbacks to obtaining accurate results. They are subjected to effects of sampling duration where long sampling times are needed to obtain adequate mass for detection. Manual samplers face challenges when measuring non-volatile species because particles are observed into the adsorption medium at a slower rate of diffusion.
Answer:
NH3 and NH4+
Explanation:
NH4+ is the conjugate acid of the base NH3.
Answer: V2 = 35.54L
Explanation:
Applying
P1= 67.4, V1= 85, T1= 245, P2= 179.6, V2= ?,. T2=273
P1V1/ T1= P2V2/T2
Substitute and simplify
(67.4*85)/245 = (179.6*V2)/273
V2= 35.54L
