Answer:
Keqq = 310
Note: Some parts of the question were missing. The missing values are used in the explanation below.
Explanation:
<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>
Using the formula ΔG° = -RT㏑Keq
㏑Keq = ΔG°/(-RT)
where ΔG° = ΔH° - TΔS°
㏑Keq = ΔH° - TΔS°/(-RT)
㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)
㏑Keq = -14221.2/-2478.968175
㏑Keq = 5.73674166
Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶
Keq = 310.05
We can use the ideal gas equation to determine the temperature with the given conditions of mass of the gas, volume, and pressure. The equation is expressed
PV=nRT where n is the number of moles equal to mass / molar mass of gas. Substituting the given conditions with R = 0.0521 L atm/mol K we can find the temperature
Answer:
The average atomic mass is 126.1
Explanation:
To obtain the atomic mass of the isotope we use this formula;
(% composition of isotope 1 * mass number) + (% composition of isotope 2 * mass number)
1. Equate the percentage composition with the mass number of each isotope
45/100 * 125 = 56.25
55/100 * 127 = 69.85
2. Add both answers together you get,
56.25 + 69.85 = 126.1.
The average atomic mass is therefore 126.1
1) Use the fact that 1 mol of gas at STP occupies 22.4 liter
=> 1 mol / 22.4 l = x / 0.125 l => x = 0.125 l * 1 mol / 22.4 l = 0.00558 mol
2) Now use the molar mass of the gas
molar mass of CO2 ≈ 44 g / mol
Formula: molar mass = mass in grams / number of moles =>
mass in grams = molar mass * number of moles = 44 g/mol * 0.00558 moles
mass = 0.246 g
Answer: 0.246 g
Answer:
Explanation:
Given
Sugar = 56g
Tea = 78g
Required
Determine the mass percent of the sugar
First we need to calculate the total mass
The percentage mass is then calculated as thus
Substitute 56 and 134 for Sugar and Total mass respectively
Approximate
<em>Hence, the percentage mass of sugar is 42%</em>