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Mice21 [21]
3 years ago
12

PLEASE HELP FAST

Chemistry
1 answer:
drek231 [11]3 years ago
8 0
The answer that makes the most sense is “c”
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Why is water a polar molecule but a fluorine molecule is not?
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Answer:

The electrons in H2O are not shared equally, making it a polar molecule. The molecules in flourine, F2, are shared equally, making it not a polar molecule.

Explanation:

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3 years ago
What the answer please help
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12.Use the equation below to determine the maximum number of grams of PH3 that can be formed when 8.2 g of phosphorus reacts wit
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Answer : The maximum number of grams of PH_3 formed is, 8.955 g

Solution : Given,

Mass of phosphorous = 8.2 g

Mass of hydrogen = 4 g

Molar mass of P_4 = 123.6 g/mole

Molar mass of H_2 = 2.016 g/mole

Molar mass of PH_3 = 33.924 g/mole

The balanced chemical reaction is,

P_4(s)+6H_2(g)\rightarrow 4PH_3(g)

First we have to calculate the moles P_4 and H_2

\text{ Moles of }P_4=\frac{\text{ Mass of }P_4}{\text{ Molar mass of }P_4}=\frac{8.2g}{123.6g/mole}=0.066moles

\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{4g}{2.016g/mole}=1.98moles

From the reaction, we conclude that

1 mole of P_4 react with 6 moles of H_2

0.066 moles of P_4 react with 6\times 0.066=0.396 moles of H_2

That means the H_2 is in excess amount and P_4 is in limited amount.

Now we have to calculate the moles of PH_3.

As, 1 mole of P_4 react to give 4 moles of PH_3

So, 0.066 moles of P_4 react to give 4\times 0.066=0.264 moles of PH_3

Now we have to calculate the mass of PH_3

\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3

\text{ Mass of }PH_3=(0.264moles)\times (33.924g/mole)=8.955g

Therefore, the maximum number of grams of PH_3 formed is, 8.955 g

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