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Kazeer [188]
3 years ago
12

There are 3 measures of music that are played 3 times in a song. If the first measure has 8 notes, the second measure has 16 not

es and the third measure has 4 notes, how many notes are played throughout the song?
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
7 0

Answer:

the correct answer would be 84

Step-by-step explanation:

Number of notes in the first two measures

8 + 16 = 24

Number of notes in the first three measures

24 + 4 = 28

Number of notes played during whole song

28 × 3 = 84

Mandarinka [93]3 years ago
5 0
Hi!

We know that there are three measures and each has a different amount of notes. To find the total we add them all up.
8+16+4=28.

There were 28 total notes played in the song.

I hope I helped you! 
Have a wonderful day!
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Explain why 256 + 4 is equivalent to (200 + 4) + (40+4) + (164)​
laiz [17]

The expression 256 + 4 is equivalent to (200 + 4) + (40+4) + (16+4) according to distributive and commutative property of addition.

Given the expression 256 + 4. This can be solved using the partial sum expressed as:

256 + 4

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= (200 + 40 + 16) + 4

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The arrangement does not affect the result. Hence;

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4 0
3 years ago
A rectangular board has a perimeter of 28 feet. if the length is twice the width minus 1 foot, then what is the length of the bo
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P = 2(L + W)
P = 28 
L = 2W - 1

28 = 2(2W - 1 + W)
28 = 2(3W - 1)
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L = 10 - 1
L = 9 <=== length is 9 ft
4 0
4 years ago
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