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lord [1]
3 years ago
8

A number line is shown below. 6 1/5 Which point is located at ? I will mark brainliest

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

I think it's the 4th one or D. N

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Being timed help asappp picture attatched
nirvana33 [79]

Answer:

The answer to your question is ∠3 = 24°

Step-by-step explanation:

Data

∠4 = 11x

∠3 = 4x

Process

1.- From the picture, we know that angles 3 and 4 are complementary so if we sum them up the result is 90°.

                                   ∠3 + ∠4 = 90°

2.- Substitution

                                    4x + 11x = 90°

3.- Simplification and result

                                            15x = 90°

                                                x = 90/15

                                               x = 6        

4.- Find angle 3

                                ∠3 = 4(6)

                                ∠3 = 24°      

6 0
3 years ago
Read 2 more answers
Subtract and simplify answer.
Schach [20]

(s^2+5st-9t^2)-(2s^2-2st+2t^2)=\\\\=s^2+5st-9t^2-2s^2+2st-2t^2=\\\\=s^2-2s^2-9t^2-2t^2+5st+2st=\boxed{-s^2-11t^2+7st}

7 0
3 years ago
Read 2 more answers
Find the value of this fraction computation: 6(1/2 + 2/3 + 3/4) Show the steps.
Marta_Voda [28]

6(1/2 + 2/3 + 3/4)

= 6(1/2) + 6(2/3) + 6(3/4)

= 3 + 4 + 4 1/2

= 11 1/2

Answer

11 1/2  (23/2 or 11.5)


7 0
4 years ago
Kelly and 23 friends go roller skating they've had a total of $186 about how much does the cost for one person to the skate
pashok25 [27]

about  8 dollars per person

5 0
4 years ago
Read 2 more answers
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
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